I decided to try making disulphane. The reaction produces all three polysulphanes. In a future post I will perform a distillation to isolate disulphane.
The first step is to prepare a solution of sodium polysulphides.
To a 500ml beaker, I poured a solution containing 17g of sodium hydroxide and 150ml of water. I added in 20g of sulphur and began boiling the mixture. The sulphur gradually dissolved and the mixture turned a beautiful dark red colour. After all the sulphur had dissolved, 120ml of dark red liquid were left. This is the polysulphide solution.
Next the sodium polysulphides must be acidified to yield the polysulphanes. All equipment used in this procedure was washed with 5% acetic acid to prevent decomposition of the polysulphanes.
In a 500ml beaker, I chilled down 20ml of the solution prepared in step one to 0 C. The reaction is best performed at -15 C but 0 C was as cold as I could get. After this temperature had been reached, I added the solution to 60ml of 33% hydrochloric acid (also chilled to 0 C). If the starting solution and the acid aren't chilled, only hydrogen sulphide and sulphur will be formed. Anyway, after the addition, a bit of hydrogen sulphide was produced along with some solid sulphur. I stirred the mixture then let it settle. After this, the polysulphanes could be seen as a vivid yellow liquid at the bottom of the container separate from the surrounding liquid.
The product was collected with a syringe and placed in an acid-washed vial. I got 0.7ml of mixed polysulphanes.
S8 + 12 NaOH = 4 Na2S + 2 Na2S2O3 + 6 H2O / S8 + 4 Na2S = 4 Na2S3
S8 + 8 Na2S = 8 Na2S2 / S8 + 2 Na2S = 2 Na2S5 / Na2Sx + 2 HCl = H2Sx + 2 NaCl
S8 + 8 Na2S = 8 Na2S2 / S8 + 2 Na2S = 2 Na2S5 / Na2Sx + 2 HCl = H2Sx + 2 NaCl